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a(n) = floor(n^2 - n^(3/2)).
1

%I #16 Sep 08 2022 08:45:11

%S 0,0,1,3,8,13,21,30,41,54,68,84,102,122,143,166,192,218,247,278,310,

%T 344,380,418,458,500,543,588,635,684,735,788,842,899,957,1017,1080,

%U 1143,1209,1277,1347,1418,1491,1567,1644,1723,1804,1886,1971,2058,2146,2236,2329

%N a(n) = floor(n^2 - n^(3/2)).

%D Richard Bean and E. S. Mahmoodian, A new bound on the size of the largest critical set in a Latin square, Discrete Math., 267 (2003), 13-21.

%H Vincenzo Librandi, <a href="/A084535/b084535.txt">Table of n, a(n) for n = 0..1000</a>

%H Richard Bean and E. S. Mahmoodian, <a href="http://arXiv.org/abs/math/0107159">A new bound on the size of the largest critical set in a Latin square</a>

%t Table[Floor[n^2-n^(3/2)],{n,0,60}] _Harvey P. Dale_, May 17 2012

%o (Magma) [Floor(n^2-n^(3/2)): n in [0..70]]; // _Vincenzo Librandi_, Sep 05 2016

%K nonn

%O 0,4

%A _N. J. A. Sloane_, Jun 29 2003