%I #10 Feb 23 2024 07:26:28
%S 2,3,15,5,35,7,39,65,51,11,95,13,115,161,87,17,155,19,111,185,123,23,
%T 215,141,235,329,159,29,371,31,183,305,427,201,335,37,219,365,511,41,
%U 395,43,415,581,267,47,623,1501,291,485,303,53,515,321,327,545,339,59
%N a(n) is the least number m such that the arithmetic mean of the distinct primes dividing m equals n.
%C Are there any terms with more than 3 prime factors?
%H Paolo P. Lava, <a href="/A082572/b082572.txt">Table of n, a(n) for n = 2..1000</a>
%e a(6) = 35 because the prime factors of 35 are {5, 7}, which have mean 6.
%Y Cf. A070009, A078177, A200612.
%K easy,nonn
%O 2,1
%A _David Wasserman_, May 06 2003
