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COMMENTS
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a(n) ~ c*(sqrt(5)+1)^n, where c = (sqrt(5)+3)/10.
The inverse binomial transform is 1,1,3,5,... (1 followed by A056487). Partial sum of 1,1,4,12,..., i.e., 1 plus n-th partial sum of A087206. [R. J. Mathar, Oct 04 2010]
Apparently the row n=4 of an array which counts walks with k steps on an n X n board, starting at a corner, each step to one of the <= 4 adjacent squares:
1,2,4,8,16,32,64,128,256,512,1024,2048,4096,
1,2,6,16,48,128,384,1024,3072,8192,24576,65536,196608,
1,2,6,18,58,186,602,1946,6298,20378,65946,213402,690586,
1,2,6,18,60,198,684,2322,8100,27702,96876,331938,1161540,
1,2,6,18,60,200,698,2432,8658,30762,110374,395428,1422916,
1,2,6,18,60,200,700,2448,8800,31552,115104,418176,1537536,
1,2,6,18,60,200,700,2450,8818,31730,116182,425172,1573416,
1,2,6,18,60,200,700,2450,8820,31750,116400,426600,1583400,
1,2,6,18,60,200,700,2450,8820,31752,116422,426862,1585246,
1,2,6,18,60,200,700,2450,8820,31752,116424,426886,1585556,
1,2,6,18,60,200,700,2450,8820,31752,116424,426888,1585582,
(End)
Decomposing rook walks of length=n on a 4 X 4 board into combinations of independent vertical and horizontal walks in 4-wide corridors leads to an exponential convolution of the Fibonacci numbers, cf. A052899. [David Scambler, Oct 17 2010]
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