|
%I #8 Jan 10 2024 16:35:12
%S 1,1,1,2,2,2,2,2,2,1,1,2,1,1,1,1,1,1,1,2,2,1,1,1,1,2,1,1,1,1,1,1,1,1,
%T 2,1,1,2,1,1,2,1,1,2,1,2,3,1,2,1,4,1,2,1,2,2,3,3,1,2,2,1,2,4,1,1,2,1,
%U 4,4,1,2,2,1,2,4,1,2,4,2,4,1,1,4,4,1,4,1,2,1,4,4,2,1,4,4,2,4,4,2,1
%N a(n) = A080969(n)/A080967(A080979(A080970(n))).
%C Donaghey shows in his paper that the orbit size (under the automorphism A057505/A057506) of each non-branch-reduced tree encoded by A080971(n) is divisible by the orbit size of the corresponding branch-reduced tree. This sequence gives the corresponding ratio.
%H Robert Donaghey, <a href="https://doi.org/10.1016/0095-8956(80)90045-3">Automorphisms on Catalan trees and bracketing</a>, J. Combin. Theory, Series B, 29 (1980), 75-90.
%K nonn
%O 0,4
%A _Antti Karttunen_, Mar 02 2003
|
