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Total number of prime factors of (prime(n)+1)*(prime(n+1)+1)/4.

5

`%I #8 Jul 13 2013 12:02:54
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`%S 1,2,3,4,3,3,4,5,5,6,5,3,4,6,7,6,4,3,6,5,5,7,6,5,4,5,7,6,4,8,9,5,5,6,
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`%T 6,4,3,6,6,6,6,8,7,4,7,6,7,8,5,5,8,7,6,6,6,8,8,5,3,4,5,6,7,5,3,4,4,5,
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`%U 6,5,7,9,6,5,10,10,4,3,4,6,5,7,8,6,7,7,5,4,7,8,10,9,6,7,9,8,6,5,3,3,5,6,6,6
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`%N Total number of prime factors of (prime(n)+1)*(prime(n+1)+1)/4.
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`%C a(n)=A001222(A079079(n)).
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`%H Reinhard Zumkeller, <a href="/A079086/b079086.txt">Table of n, a(n) for n = 1..10000</a>
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`%o (Haskell)
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`%o a079086 = a001222 . a079079 -- _Reinhard Zumkeller_, Oct 08 2012
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`%Y Cf. A079085.
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`%K nonn
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`%O 1,2
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`%A _Reinhard Zumkeller_, Dec 22 2002
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