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Numbers n in which the first k digits of n form an integer divisible by k^3, for k = 1, 2, ..., m, where m is the number of digits in n.
1

%I #1 May 16 2003 03:00:00

%S 1,2,3,4,5,6,7,8,9,16,24,32,40,48,56,64,72,80,88,96,162,243,324,405,

%T 486,567,648,729,2432,4864,7296

%N Numbers n in which the first k digits of n form an integer divisible by k^3, for k = 1, 2, ..., m, where m is the number of digits in n.

%e a(31) = 7296 because 7 is divisible by 1^3, 72 by 2^3, 729 by 3^3, 7296 by 4^3.

%Y Cf. A079042.

%K easy,fini,full,nonn,base

%O 1,2

%A Sudipta Das (juitech(AT)vsnl.net), Feb 01 2003