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A076535 a(n) = A064405 (2^m+n) - 2^m (for m large enough this difference appears to be constant). 0

%I #15 Feb 17 2016 16:20:01

%S -3,-6,-5,-12,-3,-10,-9,-24,1,-6,-5,-20,-3,-18,-17,-48,9,2,3,-12,5,

%T -10,-9,-40,9,-6,-5,-36,-3,-34,-33,-96,25,18,19,4,21,6,7,-24,25,10,11,

%U -20,13,-18,-17,-80,33,18,19,-12,21,-10,-9,-72,25,-6,-5,-68,-3,-66,-65,-192,57,50,51,36,53,38,39,8,57,42,43,12,45,14,15

%N a(n) = A064405 (2^m+n) - 2^m (for m large enough this difference appears to be constant).

%F a(n) = n + 1 - 4*A001316(n). a(0) = -3, a(2n) = a(n) + n, a(2n+1) = 2a(n). - _Ralf Stephan_, Oct 08 2003

%e For n=17; for m=1,2,3,4,5,6,7,8,9,10 values of A064405 (2^m+17) - 2^m are .... 2,2,2,10,2,2,2,2,2,2, so for n>4 the difference seems always equal to 2, hence a(17)=2

%o (PARI) A001316(n)=sum(k=0,n,binomial(n,k)%2)

%o for(n=0,100,print1(n+1-4*A001316(n),",")) \\ Lambert Klasen

%Y Cf. A064405.

%K sign

%O 0,1

%A _Benoit Cloitre_, Oct 18 2002

%E More terms from Lambert Klasen (lambert.klasen(AT)gmx.de), Jan 14 2005

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Last modified March 28 21:54 EDT 2024. Contains 371254 sequences. (Running on oeis4.)