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a(n) = 2^n + 3^n + 8^n.
1

%I #16 Sep 08 2022 08:45:07

%S 3,13,77,547,4193,33043,262937,2099467,16784033,134237923,1073801897,

%T 8590113787,68720012273,549757416403,4398051310457,35184386470507,

%U 281475019822913,2251799942956483,18014398897164617,144115189238641627

%N a(n) = 2^n + 3^n + 8^n.

%H Vincenzo Librandi, <a href="/A074530/b074530.txt">Table of n, a(n) for n = 0..200</a>

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (13,-46,48).

%F From _Mohammad K. Azarian_, Dec 27 2008: (Start)

%F G.f.: 1/(1-2*x) + 1/(1-3*x) + 1/(1-8*x).

%F E.g.f.: exp(2*x) + exp(3*x) + exp(8*x). (End)

%t Table[2^n + 3^n + 8^n, {n, 0, 20}]

%o (Magma) [2^n + 3^n + 8^n: n in [0..25]]; // _Vincenzo Librandi_, Jun 11 2011

%Y Cf. A001550, A001576, A034513, A001579, A074501 - A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002