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%I #6 Mar 30 2012 17:27:38
%S 1,2,14,22,12
%N Numbers k such that A073142(n) = f^k(A073142(n)), where f: m -> |m - reverse(m)|.
%C Presumably a(6) = 17. a(n) is the length of the periodic part (cf. A072137) of the trajectory of A073142(n). Question: Does every k > 0 appear in this sequence?
%e a(3) = 14 since A073142(2) = 11436678 is the smallest solution of x = f^14(x).
%Y Cf. A072137, A072141, A072142, A072143, A072718, A072719, A073142, A073144.
%K base,more,nonn
%O 1,2
%A _Klaus Brockhaus_, Jul 17 2002
%E Offset changed by _N. J. A. Sloane_, Dec 01 2007
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