%I
%S 5,12,26,31,35,51,56,60,136,152,157,177,182,252,257,275,280,287,300,
%T 305,312,627,632,650,655,662,675,680,687,751,756,760,786,811,886,902,
%U 907,927,932,1251,1256,1260,1286,1311,1377,1382,1400,1405,1412,1425
%N Numbers n such that the final nonzero digit of n! is the same as the last digit of C(2n,n) (in base 10).
%F n such that A008904(n) = C(2n, n) reduced (mod 10)
%e 12! = 479001600 C(24,12)= 2704156 and the last nonzero digit of 12! is the same as the last digit of C(24,12) hence 12 is in the sequence.
%K base,easy,nonn
%O 1,1
%A _Benoit Cloitre_, Aug 18 2002
