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A073095 Numbers n such that the final nonzero digit of n! is the same as the last digit of C(2n,n) (in base 10). 0

%I

%S 5,12,26,31,35,51,56,60,136,152,157,177,182,252,257,275,280,287,300,

%T 305,312,627,632,650,655,662,675,680,687,751,756,760,786,811,886,902,

%U 907,927,932,1251,1256,1260,1286,1311,1377,1382,1400,1405,1412,1425

%N Numbers n such that the final nonzero digit of n! is the same as the last digit of C(2n,n) (in base 10).

%F n such that A008904(n) = C(2n, n) reduced (mod 10)

%e 12! = 479001600 C(24,12)= 2704156 and the last nonzero digit of 12! is the same as the last digit of C(24,12) hence 12 is in the sequence.

%K base,easy,nonn

%O 1,1

%A _Benoit Cloitre_, Aug 18 2002

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Last modified July 25 16:39 EDT 2021. Contains 346291 sequences. (Running on oeis4.)