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%I #3 Mar 30 2012 18:51:38
%S 1,4,823
%N Integers which are exactly the concatenation of the first m numbers (A007908) divided by their sum (A000217 = m*(m+1)/2).
%C A probability argument suggests that this sequence may be finite.
%e a(1) = 1/1 =1; a(2) = 12/(1+2) = 4; a(3) = 12345/(1+2+3+4+5).
%Y Cf. A067116, A072723, A072724.
%K base,nonn,bref
%O 1,2
%A _Henry Bottomley_, Jul 06 2002
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