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A072491 Define f(1) = 0. For n>=2, let f(n) = n - p where p is the largest prime <= n. a(n) = number of iterations of f to reach 0, starting from n. 4

%I #21 Aug 09 2015 14:06:15

%S 0,1,1,1,2,1,2,1,2,2,2,1,2,1,2,2,2,1,2,1,2,2,2,1,2,2,2,3,2,1,2,1,2,2,

%T 2,3,2,1,2,2,2,1,2,1,2,2,2,1,2,2,2,3,2,1,2,2,2,3,2,1,2,1,2,2,2,3,2,1,

%U 2,2,2,1,2,1,2,2,2,3,2,1,2,2,2,1,2,2,2,3,2,1,2,2,2,3,2,3,2,1,2,2,2,1,2,1,2,2

%N Define f(1) = 0. For n>=2, let f(n) = n - p where p is the largest prime <= n. a(n) = number of iterations of f to reach 0, starting from n.

%C a(p)=1, a(p+1)=2 and a(p+4)=3 if p is an odd prime but p+2 and p+4 are composite.

%C Number of noncomposites (A008578) needed to sum to n using the greedy algorithm. - _Antti Karttunen_, Aug 09 2015

%D S. S. Pillai, "An arithmetical function concerning primes", Annamalai University Journal (1930), pp. 159-167.

%H Antti Karttunen, <a href="/A072491/b072491.txt">Table of n, a(n) for n = 0..10007</a>

%F On Cramér's conjecture, a(n) = O(log* n). - _Charles R Greathouse IV_, Feb 04 2013

%e a(27)=3 as f(27)=27-23=4, f(4)=4-3=1 and f(1)=0.

%t f[1]=0; f[n_] := n-Prime[PrimePi[n]]; a[n_] := Module[{k, x}, For[k=0; x=n, x>0, k++; x=f[x], Null]; k]

%o (PARI) a(n)=if(n<4,n>0,1+a(n-precprime(n))) \\ _Charles R Greathouse IV_, Feb 04 2013

%Y Cf. A008578, A072492. A066352(n) is the smallest k such that a(k)=n.

%Y Not the same as A051034: a(122) = 3, but A051034(122) = 2.

%K nonn,easy

%O 0,5

%A _Amarnath Murthy_, Jul 14 2002

%E Edited by _Dean Hickerson_, Nov 26 2002

%E a(0) = 0 prepended by _Antti Karttunen_, Aug 09 2015

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Last modified April 24 10:00 EDT 2024. Contains 371935 sequences. (Running on oeis4.)