%I #14 May 10 2019 17:55:02
%S 2,4,22,63,4202,4246,444886,1161238,9362914,26996486,545614671,
%T 1640386293,2242930954,2243031802,2243065418,2243115842,18000691527
%N Numbers k such that sigma(k) = (Pi^2)*(k/6) rounded off (where 0.5 is rounded to 0).
%C In 1838 Dirichlet showed that the average value of sigma(n) is (Pi^2)*(n/6) for large n (see Tattersall).
%D Tattersall, J. "Elementary Number Theory in Nine Chapters", Cambridge University Press, 1999.
%e sigma(444886) = 731808 = (Pi^2 * 444886)/6 rounded off; so 444886 is a term of the sequence.
%t Select[Range[10^6], Round[(Pi^2 * #)/6] == DivisorSigma[1, # ] &]
%Y Cf. A013661 (Pi^2/6), A074920.
%K nonn,more
%O 1,1
%A _Joseph L. Pe_, Jul 18 2002
%E More terms from _Robert G. Wilson v_, Jul 27 2002
%E a(10)-a(17) from _Giovanni Resta_, Apr 03 2017
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