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%I #9 Feb 11 2014 19:05:28
%S 1,168,1141,1451,2139,2737,3938,7597,11831,19668,21415,23649,31894,
%T 32383,40649,52687,59677,121023,133661,136831,146055,148503,172095,
%U 190035,245998,276058,302005,302503,307705,396635,410389,504557,516439,539327,571577
%N Numbers n such that phi(reverse(n)) = sigma(n).
%H Donovan Johnson, <a href="/A070835/b070835.txt">Table of n, a(n) for n = 1..500</a>
%e phi(reverse(168)) = phi(861) = 480 = sigma(168), so 168 is a term of the sequence.
%t Select[Range[10^5], EulerPhi[FromDigits[Reverse[IntegerDigits[ # ]]]] == DivisorSigma[1, # ] &]
%Y Cf. A000203, A000010, A004086, A070856.
%K base,nonn
%O 1,2
%A _Joseph L. Pe_, May 16 2002
%E More terms from _Labos Elemer_, Jul 04 2003
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