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A070442
a(n) = n^2 mod 20.
13
0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16, 5, 16, 9, 4, 1, 0, 1, 4, 9, 16
OFFSET
0,3
COMMENTS
Also, n^6 mod 20.
Equivalently n^10 mod 20. - Zerinvary Lajos, Oct 31 2009
FORMULA
From Reinhard Zumkeller, Apr 24 2009: (Start)
a(m*n) = a(m)*a(n) mod 20.
a(5*n+k) = a(5*n-k) for k <= 5*n.
a(n+10) = a(n). (End)
G.f. -x*(1+4*x+9*x^2+16*x^3+5*x^4+16*x^5+9*x^6+4*x^7+x^8) / ( (x-1) *(1+x) *(x^4+x^3+x^2+x+1) *(x^4-x^3+x^2-x+1) ). - R. J. Mathar, Aug 27 2013
MATHEMATICA
Table[Mod[n^2, 20], {n, 0, 200}] (* Vladimir Joseph Stephan Orlovsky, Apr 23 2011 *)
LinearRecurrence[{0, 0, 0, 0, 0, 0, 0, 0, 0, 1}, {0, 1, 4, 9, 16, 5, 16, 9, 4, 1}, 95] (* Ray Chandler, Aug 26 2015 *)
PowerMod[Range[0, 100], 2, 20] (* or *) PadRight[{}, 120, {0, 1, 4, 9, 16, 5, 16, 9, 4, 1}] (* Harvey P. Dale, Jan 06 2019 *)
PROG
(Sage) [power_mod(n, 10, 20) for n in range(0, 88)] # Zerinvary Lajos, Oct 31 2009
(PARI) a(n)=n^2%20 \\ Charles R Greathouse IV, Jun 11 2015
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, May 12 2002
STATUS
approved