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A069951 Continued fraction expansion of the number e^(2/3). 3

%I #9 Mar 17 2015 23:06:17

%S 1,1,18,7,1,1,10,54,16,1,1,19,90,25,1,1,28,126,34,1,1,37,162,43,1,1,

%T 46,198,52,1,1,55,234,61,1,1,64,270,70,1,1,73,306,79,1,1,82,342,88,1,

%U 1,91,378,97,1,1,100,414,106,1,1,109,450,115,1,1,118,486,124,1,1,127,522

%N Continued fraction expansion of the number e^(2/3).

%C e^(2/3) = 1.9477340410546758566390...

%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>

%H K. Matthews, <a href="http://www.numbertheory.org/php/davison.html">Finding the continued fraction of e^(l/m)</a>

%F If k>0 a(5k)=a(5k+1)=1, a(5k+2)=9k+1, a(5k+3)=36k+18, a(5k+4)=9k+7. - _Benoit Cloitre_, May 04 2002

%t ContinuedFraction[ E^(2/3), 100]

%K nonn,cofr,easy

%O 0,3

%A Elena Andres Sierra (aeroplane27(AT)hotmail.com), Apr 27 2002

%E Edited and extended by _Robert G. Wilson v_ and _Benoit Cloitre_, May 04 2002

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