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%I #23 Mar 18 2024 09:50:58
%S 1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,
%T 1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,
%U 3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1,1,1,2,3,5,4,3,1
%N a(n) = round((a(n-1) + a(n-2))/a(n-3)) starting with a(1)=a(2)=a(3)=1.
%C While this sequence has period 8, the unrounded version b(n) = (b(n-1) + b(n-2))/b(n-3) seems to have a quasi-period of about 8.7 for this particular starting point.
%C The unrounded version b(n) = A185332(n) / A185341(n) as given in A205303 has 8.694171... quasi-period. - _Michael Somos_, Oct 22 2018
%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,1).
%F a(n) = a(n-8).
%e a(7) = round((a(6) + a(5))/a(4)) = round((5+3)/2) = 4.
%Y Cf. A048112, A185332, A185341, A205303.
%K nonn,easy
%O 1,4
%A _Henry Bottomley_, Mar 25 2002
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