|
%I #8 Oct 02 2023 16:53:27
%S 0,5,1309,6930626021,69276127053913,55161685571748368516129,
%T 60704287720766467657420739188688372093,
%U 14219718499310404733294067750922248714893617,1325029748371862191613733461029305453409268582295864406779661
%N Let p be a prime of the form 4k-1; sequence gives (q!^2-1)/p where q = (p-1)/2.
%H Ed Pegg, Jr., <a href="http://www.mathpuzzle.com">Math. Puzzles</a>
%F a(n) = (q!^2-1)/p where q=(p-1)/2 and p = A002145(n). - _Sean A. Irvine_, Oct 02 2023
%Y Cf. A002145.
%K nonn
%O 1,2
%A _N. J. A. Sloane_, Dec 13 2001
%E Missing a(1)=0 inserted by _Sean A. Irvine_, Oct 02 2023
| 