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A065560
a(n) is the smallest integer k such that floor((1+1/n)^(k+1))/floor((1+1/n)^k) = 1+1/n.
4
2, 4, 7, 9, 12, 15, 18, 21, 25, 28, 40, 35, 39, 42, 46, 50, 54, 58, 62, 66, 70, 74, 78, 83, 87, 91, 95, 100, 104, 109, 113, 118, 122, 127, 131, 136, 141, 145, 150, 155, 159, 164, 169, 174, 179, 183, 188, 193, 198, 203, 208, 213, 218, 223, 228, 233, 238, 243, 248, 253
OFFSET
2,1
COMMENTS
a(n) is growing roughly like prime(n). a(n) < a(n+1) except for n = 12. (Is this the only exception?)
a(n) < a(n+1) except for n = 12, 108, 266, ... - Boris Gourevitch (boris(AT)pi314.net), Dec 04 2001
Conjecture: a(n)+n > prime(n).
LINKS
FORMULA
Asymptotic (conjectured) formula: a(n)=n*log(n)+o(log(n)).
EXAMPLE
a(5) = 9 because 9 is the first integer satisfying floor((6/5)^(9+1))/floor((6/5)^9) = 6/5.
PROG
(PARI) a(n) = { my(k=1, f=(n + 1)/n); while((floor(f^(k + 1))/floor(f^k)) != f, k++); k } \\ Harry J. Smith, Oct 22 2009
CROSSREFS
Sequence in context: A189379 A226595 A031435 * A134886 A024193 A064550
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Nov 29 2001
EXTENSIONS
Terms a(53) - a(61) from Harry J. Smith, Oct 22 2009
STATUS
approved