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 A064025 Length of period of the continued fraction for sqrt(n!). 2
 1, 2, 2, 2, 4, 2, 16, 48, 8, 4, 56, 180, 44, 156, 300, 7936, 10388, 11516, 9104, 13469268, 2684084, 2418800, 28468692, 143007944, 85509116, 402570696, 2287868888, 204306960, 48715166536, 147160740856, 317585614148 (list; graph; refs; listen; history; text; internal format)
 OFFSET 2,2 LINKS FORMULA a(n) = A003285(A000142(n)). - Michel Marcus, Sep 25 2019 EXAMPLE Quotients for 10! are [[1904], [1, 15, 1, 13, 1, 15, 1, 3808]], so period length of 10! is 8. MAPLE with(numtheory): [seq(nops(cfrac(sqrt(k!), 'periodic', 'quotients')[2]), k=2..16)]; MATHEMATICA Do[ Print[ Length[ Last[ ContinuedFraction[ Sqrt[ n! ]]]]], {n, 2, 24} ] CROSSREFS Cf. A000142, A003285. Sequence in context: A135293 A216951 A320305 * A182154 A273875 A054709 Adjacent sequences:  A064022 A064023 A064024 * A064026 A064027 A064028 KEYWORD nonn,more AUTHOR Labos Elemer, Sep 18 2001 EXTENSIONS More terms from Robert G. Wilson v, Oct 01 2001 a(25)-a(28) from Daniel Suteu, Jan 24 2019 a(29) from Chai Wah Wu, Sep 23 2019 a(30) from Chai Wah Wu, Sep 25 2019 a(31) from Chai Wah Wu, Jan 27 2021 a(32) from Chai Wah Wu, Feb 02 2021 STATUS approved

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Last modified May 14 07:13 EDT 2021. Contains 343879 sequences. (Running on oeis4.)