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A062215 Numbers k such that the smoothly undulating palindromic number (19*10^k - 91)/99 is a prime. 0

%I #14 Oct 30 2019 01:01:08

%S 3,33,133,1969,2335

%N Numbers k such that the smoothly undulating palindromic number (19*10^k - 91)/99 is a prime.

%C Prime versus probable prime status and proofs are given in the author's table.

%C No further terms < 100000. - _Ray Chandler_, Aug 17 2011

%H P. De Geest, <a href="http://www.worldofnumbers.com/undulat.htm#supp191">SUPP Reference Table - 191</a>

%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>

%e k=33 -> (19*10^33 - 91)/99 = 191919191919191919191919191919191.

%Y Cf. A062209-A062232, A059758, A032758.

%K nonn,base

%O 1,1

%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001

%E Edited by _Ray Chandler_, Aug 17 2011

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Last modified March 29 08:01 EDT 2024. Contains 371265 sequences. (Running on oeis4.)