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a(n) = (2^A000959(n)) - 1.
0

%I #8 Feb 24 2020 08:40:35

%S 1,7,127,511,8191,32767,2097151,33554431,2147483647,8589934591,

%T 137438953471,8796093022207,562949953421311,2251799813685247,

%U 9223372036854775807,147573952589676412927,590295810358705651711,9444732965739290427391,37778931862957161709567

%N a(n) = (2^A000959(n)) - 1.

%Y Cf. A000959, A061743, A000668.

%K nonn

%O 1,2

%A _Jason Earls_, May 07 2001