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 A061583 a(1) = 1, a(n) is the number obtained by replacing each digit of a(n-1) with five times its value. 4

%I

%S 1,5,25,1025,501025,250501025,10250250501025,501025010250250501025,

%T 2505010250501025010250250501025,

%U 1025025050102502505010250501025010250250501025

%N a(1) = 1, a(n) is the number obtained by replacing each digit of a(n-1) with five times its value.

%C Number of digits of each term is the sequence A038718. - _Dmitry Kamenetsky_, Jan 17 2009

%H John Cerkan, <a href="/A061583/b061583.txt">Table of n, a(n) for n = 1..17</a>

%p a:= proc(n) option remember; `if`(n=1, 1, (s-> parse(cat(

%p seq(parse(s[i])*5, i=1..length(s)))))(""||(a(n-1))))

%p end:

%p seq(a(n), n=1..10); # _Alois P. Heinz_, May 25 2018

%t NestList[FromDigits[Flatten[IntegerDigits/@(5*IntegerDigits[#])]]&,1,10] (* _Harvey P. Dale_, Dec 31 2013 *)

%o (Python)

%o def A061583_first(n):

%o an = "1"

%o a061583 = []

%o while n > 1:

%o a061583.append(int(an))

%o newan = ""

%o for i in an:

%o newan += str(5*int(i))

%o an = newan

%o n -= 1

%o a061583.append(int(an))

%o return a061583 # _John Cerkan_, May 25 2018

%Y Cf. A061581, A061582, A061584, A061585, A061586, A061587.

%K nonn,base,easy

%O 1,2

%A _Amarnath Murthy_, May 13 2001

%E More terms from Larry Reeves (larryr(AT)acm.org) and Asher Natan Auel (auela(AT)reed.edu), May 15 2001

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Last modified August 2 02:53 EDT 2021. Contains 346409 sequences. (Running on oeis4.)