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%I #6 Oct 14 2022 17:57:58
%S 1,4,18,1,16,324,72030,162,1,64,5832,2916,372027810,10588410,1458,1,
%T 256,104976,1036385881030500,26244,9421689827550,4946387159463750,
%U 1556496270,13122,1,1024,1889568,2542277241000,76256028326940,236196
%N Periodic part of continued fraction for sqrt(n), encoded by raising successive primes to the terms. If sqrt(n)=c0+[c1,c2,c3...] then a(n)=2^c1*3^c2*5^c3*...
%C Could be made less gigantic by omitting final terms in continued fraction, which are always 2*c0.
%F a(n) = A059900(A059904(n)).
%e sqrt(14) = 3+[1,2,1,6] so a(14) = 2^1*3^2*5^1*7^6 = 10588410.
%Y Cf. A059904, A059900, A003285.
%K easy,nonn
%O 1,2
%A _Marc LeBrun_, Feb 07 2001
%E Offset corrected by _Sean A. Irvine_, Oct 14 2022