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%I #14 May 01 2021 06:48:51
%S 1,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,
%T 5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,
%U 5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2,5,2
%N Period of continued fraction for sqrt(n^2+4), n >= 1.
%C From _Jianing Song_, May 01 2021: (Start)
%C The old name was "Quotient cycle length of sqrt(n^2+4)."
%C Essentially the same as A010695 and A021400. (End)
%F a(n) = 2 for even n, a(n) = 5 for odd n > 1.
%F a(n) = A003285(n^2+4). - _Jianing Song_, May 01 2021
%e For even n, sqrt(n^2+4) = [n; n/2, 2*n], hence a(n) = 2.
%e For odd n > 1, sqrt(n^2+4) = [n; (n-1)/2, 1, 1, (n-1)/2, 2*n], hence a(n) = 5.
%p with(numtheory): [seq(nops(cfrac(sqrt(k^2+4), 'periodic', 'quotients')[2]), k=1..100)];
%t a[n_] := Length @ ContinuedFraction[Sqrt[n^2 + 4]][[2]]; Array[a, 100] (* _Amiram Eldar_, May 13 2020 *)
%Y Cf. A003285, A010695, A021400.
%Y Period of continued fraction for sqrt(n^2+k): A059853 (k=3), this sequence (k=4), A059854 (k=5).
%K nonn,easy
%O 1,2
%A _Labos Elemer_, Feb 27 2001
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