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%I #7 Apr 06 2015 10:46:21
%S 7,14,17,23,28,31,34,41,46,49,47,56,63,68,71,62,73,82,89,94,97,79,92,
%T 103,112,119,124,127,98,113,126,137,146,153,158,161,119,136,151,164,
%U 175,184,191,196,199,142,161,178,193,206,217,226,233,238,241,167,188
%N Triangle of numbers related to congruum problem: T(n,k)=n^2+2nk-k^2 with n>k>0, starting at T(2,1)=7.
%C The congruum problem is to find h (A057103) such that there are integers x (A055096), y (A057105) and z (A056203) with h=x^2-y^2=z^2-x^2.
%C Refers to A057102, which had an incorrect description and has been replaced by A256418. As a result the present sequence should be re-checked. - _N. J. A. Sloane_, Apr 06 2015
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/CongruumProblem.html">Congruum Problem.</a>
%F a(n) = sqrt(A057103(n)+A055096(n)^2) = sqrt(2*A057103(n)+A057105(n)^2).
%e a(1) = T(2,1) = 2^2+2*2*1-1 = 7.
%Y Cf. A057102.
%K nonn,tabl
%O 1,1
%A _Henry Bottomley_, Aug 02 2000
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