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A052931
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Expansion of 1/(1 - 3*x^2 - x^3).
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9
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1, 0, 3, 1, 9, 6, 28, 27, 90, 109, 297, 417, 1000, 1548, 3417, 5644, 11799, 20349, 41041, 72846, 143472, 259579, 503262, 922209, 1769365, 3269889, 6230304, 11579032, 21960801, 40967400, 77461435, 144863001, 273351705, 512050438, 964918116, 1809503019
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OFFSET
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0,3
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COMMENTS
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Let A be the tridiagonal unit-primitive matrix (see [Jeffery]) A = A_{9,1} = [0,1,0,0; 1,0,1,0; 0,1,0,1; 0,0,1,1]. Then a(n)=[A^n]_(2,3). - L. Edson Jeffery, Mar 19 2011
This sequence a(n) appears in the formula for the nonnegative powers of the algebraic number rho(9) := 2*cos(Pi/9) of degree 3, the ratio of the smallest diagonal/side in the regular 9-gon, in terms of the power basis of the algebraic number field Q(rho(9)) (see A187360, n=9).
rho(9)^n = A(n)*1 + B(n)*rho(9) + C(n)*rho(9)^2, with A(0) = 1, A(1) = 0, A(n) = B(n-2), n >= 2, B(0) = 0, B(n) = a(n-1), n >= 1, C(0) = 0, C(n) = B(n-1), n >= 1. (End)
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LINKS
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FORMULA
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G.f.: 1/(1-3*x^2-x^3).
a(n) = 3*a(n-2) + a(n-3), with a(0)=1, a(1)=0, a(2)=3.
a(n) = Sum_{alpha=RootOf(-1+3*z^2+z^3)} (1/9)*(-1 +5*alpha +2*alpha^2) * alpha^(-1-n).
a(n) = Sum_{k=0..floor(n/2)} binomial(k, n-2k)3^(3k-n). - Paul Barry, Oct 04 2004
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EXAMPLE
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In the 9-gon (enneagon), powers of rho(9) = 2*cos(pi/9):
rho(9)^5 = A(5)*1 + B(5)*rho(9) + C(5)*rho(9)^2, with A(5) = B(3) = a(2) = 3, B(5) = a(4) = 9 and C(5) = B(4) = a(3) = 1:
rho(9)^5 = 3 + 9*rho(9) + rho(9)^2. (End)
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MAPLE
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spec := [S, {S=Sequence(Prod(Z, Union(Z, Z, Z, Prod(Z, Z))))}, unlabeled]: seq(combstruct[count](spec, size=n), n=0..20);
seq(coeff(series(1/(1-3*x^2-x^3), x, n+1), x, n), n = 0..40); # G. C. Greubel, Oct 17 2019
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MATHEMATICA
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CoefficientList[Series[1/(1-3x^2-x^3), {x, 0, 40}], x] (* or *) LinearRecurrence[{0, 3, 1}, {1, 0, 3}, 40] (* Vladimir Joseph Stephan Orlovsky, Jan 28 2012 *)
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PROG
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(PARI) x='x+O('x^40); Vec(1/(1-3*x^2-x^3)) \\ Altug Alkan, Feb 20 2018
(Magma) R<x>:=PowerSeriesRing(Integers(), 40); Coefficients(R!( 1/(1-3*x^2-x^3) )); // G. C. Greubel, Oct 17 2019
(Sage)
P.<x> = PowerSeriesRing(ZZ, prec)
return P(1/(1-3*x^2-x^3)).list()
(GAP) a:=[1, 0, 3];; for n in [4..40] do a[n]:=3*a[n-2]+a[n-3]; od; a; # G. C. Greubel, Oct 17 2019
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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encyclopedia(AT)pommard.inria.fr, Jan 25 2000
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EXTENSIONS
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STATUS
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approved
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