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A051191 a(n) = 2^(2^n-2). 2

%I #13 Mar 22 2022 18:53:11

%S 1,4,64,16384,1073741824,4611686018427387904,

%T 85070591730234615865843651857942052864,

%U 28948022309329048855892746252171976963317496166410141009864396001978282409984

%N a(n) = 2^(2^n-2).

%C The next term, a(9), has 154 digits. - _Harvey P. Dale_, Apr 13 2012

%H Michael De Vlieger, <a href="/A051191/b051191.txt">Table of n, a(n) for n = 1..11</a>

%H Delbrin Ahmed, <a href="http://www.math.u-szeged.hu/~czedli/dr-reposit/phdtheses/delbrin-ahmed-d.pdf">On subuniverses of lattices and semilattices</a>, Ph. D. Thesis, Univ. of Szeged (Hungary, 2022).

%t 2^(2^Range[9]-2) (* _Harvey P. Dale_, Apr 13 2012 *)

%K nonn,easy

%O 1,2

%A Matt Kasper (matt192837(AT)hotmail.com)

%E a(8) from _Harvey P. Dale_, Apr 13 2012

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Last modified April 25 05:18 EDT 2024. Contains 371964 sequences. (Running on oeis4.)