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a(1)=a(2)=1, then a(n+1) = floor(a(n)/3) if this is not among 0, a(1), ..., a(n); otherwise a(n+1) = a(n) + a(n-1).
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%I #20 Oct 09 2019 03:05:04

%S 1,1,2,3,5,8,13,4,17,21,7,28,9,37,12,49,16,65,81,27,108,36,144,48,192,

%T 64,256,85,341,113,454,151,50,201,67,22,89,29,118,39,157,52,209,69,23,

%U 92,30,10,40,50,90,140,46,15,61,20,6,26,32

%N a(1)=a(2)=1, then a(n+1) = floor(a(n)/3) if this is not among 0, a(1), ..., a(n); otherwise a(n+1) = a(n) + a(n-1).

%C Numbers appearing among the terms more than once include 1, 50, 265, 341, 516, 570, 622, ... - _Ivan Neretin_, Sep 04 2015

%H Ivan Neretin, <a href="/A050416/b050416.txt">Table of n, a(n) for n = 1..10000</a>

%t a = {0, 1, 1}; Do[AppendTo[a, If[MemberQ[a, c = Quotient[a[[-1]], 3]], a[[-1]] + a[[-2]], c]], {n, 3, 59}]; Delete[a, 1] (* _Ivan Neretin_, Sep 04 2015 *)

%Y Cf. A050417.

%Y Cf. A050000, A050004, A050076, A050080, A050084, A050104, A050124, A050128, A050132, A050135, A050136, A050137, A050138, A050139, A050170, A050196.

%K nonn

%O 1,3

%A _Clark Kimberling_