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Continued fraction for sqrt(865).
1

%I #11 Mar 10 2017 16:45:21

%S 29,2,2,3,3,1,1,1,2,6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,

%T 1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,

%U 6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,1

%N Continued fraction for sqrt(865).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_19">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(865)),confrac);

%t ContinuedFraction[Sqrt[865],100] (* _Harvey P. Dale_, Nov 27 2012 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.