%I #11 Mar 10 2017 16:45:21
%S 29,2,2,3,3,1,1,1,2,6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,
%T 1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,
%U 6,6,2,1,1,1,3,3,2,2,58,2,2,3,3,1,1,1,2,6,6,2,1,1,1
%N Continued fraction for sqrt(865).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_19">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(865)),confrac);
%t ContinuedFraction[Sqrt[865],100] (* _Harvey P. Dale_, Nov 27 2012 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.