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Continued fraction for sqrt(263).
0

%I #16 Dec 27 2023 00:01:14

%S 16,4,1,1,1,1,15,1,1,1,1,4,32,4,1,1,1,1,15,1,1,1,1,4,32,4,1,1,1,1,15,

%T 1,1,1,1,4,32,4,1,1,1,1,15,1,1,1,1,4,32,4,1,1,1,1,15,1,1,1,1,4,32,4,1,

%U 1,1,1,15,1,1,1,1,4,32,4,1,1,1,1,15,1,1,1,1,4,32,4,1

%N Continued fraction for sqrt(263).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(263)),confrac);

%t ContinuedFraction[Sqrt[263],120] (* or *) PadRight[{16},120,{32,4,1,1,1,1,15,1,1,1,1,4}] (* _Harvey P. Dale_, Nov 23 2019 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.