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A040155 Continued fraction for sqrt(168). 1

%I #25 Nov 22 2023 08:31:07

%S 12,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,

%T 1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,24,1,

%U 24,1,24,1,24,1,24,1,24,1,24,1

%N Continued fraction for sqrt(168).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (0,1).

%F From _Amiram Eldar_, Nov 22 2023: (Start)

%F Multiplicative with a(2^e) = 24, and a(p^e) = 1 for an odd prime p.

%F Dirichlet g.f.: zeta(s) * (1 + 23/2^s). (End)

%p Digits := 100: convert(evalf(sqrt(N)),confrac,90,'cvgts'):

%t ContinuedFraction[Sqrt[168],300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 25 2011 *)

%t PadRight[{12},120,{24,1}] (* _Harvey P. Dale_, Dec 17 2013 *)

%K nonn,cofr,easy,mult

%O 0,1

%A _N. J. A. Sloane_

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Last modified April 24 08:59 EDT 2024. Contains 371935 sequences. (Running on oeis4.)