%I #27 Dec 26 2023 23:59:40
%S 12,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,
%T 4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,
%U 24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4,24,4
%N Continued fraction for sqrt(150).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (0,1).
%p Digits := 100: convert(evalf(sqrt(N)),confrac,90,'cvgts'):
%t ContinuedFraction[Sqrt[150],300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 13 2011*)
%o (Python)
%o from sympy import sqrt
%o from sympy.ntheory.continued_fraction import continued_fraction_iterator
%o def aupton(nn):
%o gen = continued_fraction_iterator(sqrt(150))
%o return [next(gen) for i in range(nn+1)]
%o print(aupton(73)) # _Michael S. Branicky_, Dec 04 2021
%o (Python) # second version based on recurrence
%o def a(n): return 12 if n == 0 else [4, 24][(n-1)%2]
%o print([a(n) for n in range(74)]) # _Michael S. Branicky_, Dec 04 2021
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.