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A040055 Continued fraction for sqrt(63). 4

%I #30 Nov 13 2023 07:07:09

%S 7,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,

%T 14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,1,14,

%U 1,14,1,14,1,14,1,14,1,14,1

%N Continued fraction for sqrt(63).

%H Harry J. Smith, <a href="/A040055/b040055.txt">Table of n, a(n) for n = 0..20000</a>

%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>.

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (0,1).

%F From _Amiram Eldar_, Nov 13 2023: (Start)

%F Multiplicative with a(2^e) = 14, and a(p^e) = 1 for p >= 5.

%F Dirichlet g.f.: zeta(s) * (1 + 13/2^s). (End)

%e 7.9372539331937717715048472... = 7 + 1/(1 + 1/(14 + 1/(1 + 1/(14 + ...)))). - _Harry J. Smith_, Jun 07 2009

%p Digits := 100: convert(evalf(sqrt(N)),confrac,90,'cvgts'):

%t ContinuedFraction[Sqrt[63], 300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 08 2011 *)

%o (PARI) { allocatemem(932245000); default(realprecision, 25000); x=contfrac(sqrt(63)); for (n=0, 20000, write("b040055.txt", n, " ", x[n+1])); } \\ _Harry J. Smith_, Jun 07 2009

%Y Cf. A010516 (decimal expansion), A020820 (decimal expansion of 1/sqrt(63)).

%K nonn,cofr,easy,mult

%O 0,1

%A _N. J. A. Sloane_

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Last modified April 25 11:06 EDT 2024. Contains 371967 sequences. (Running on oeis4.)