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%I #6 Mar 30 2012 18:56:32
%S 0,0,0,0,1,0,1,2,3,2,1,0,1,2,3,2,1,0,1,4,3,2,1,0,1,0,1,2,3,1,0,1,2,3,
%T 1,0,1,2,3,1,0,1,2,3,1,0,1,2,3,2,1,0,1,2,2,1,0,1,2,2,1,0,1,2,2,1,0,1,
%U 2,2,1,0,1,2,3,2,1,0,1,3,2,1,0,1,3,2,1,0,1,3
%N a(n)=(1/2)*Sum{|d(i)-e(i)|} where Sum{d(i)*5^i} is the base 5 representation of n and e(i) are the digits d(i) in reverse order.
%K nonn,base
%O 1,8
%A _Clark Kimberling_
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