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%I #13 Dec 09 2017 04:01:45
%S 2,3,6,11,21,39,69,119,199,323,795,829,866,903,942,982,1024,1067,1113,
%T 1159,1208,1258,1310,1364,1420,1478,1539,1601,1665,1732,1802,1873,
%U 1948,2024,2104,2186,2271,2360,2451,2545,2642,2743,2847,2955,3066,3181,3300
%N a(0)=2; a(n) is the smallest k > a(n-1) such that the fractional part of k^(1/9) starts with n.
%F For n > 0, a(n) = ceiling((d + n/10^d)^9) where d = 1 + floor(log_10(n)). - _Jon E. Schoenfield_, Dec 09 2017
%e a(9) = 323 -> 323^(1/9) = 1.{9}0020422...;
%e a(10) = 795 -> 795^(1/9) = 2.{10}021141... and a(9)=323 < a(10)=795.
%e From _Jon E. Schoenfield_, Dec 09 2017: (Start)
%e n a(n) a(n)^(1/9)
%e -- ------ ---------------
%e 0 2 1.{0}8005973...
%e 1 3 1.{1}2983096...
%e 2 6 1.{2}2028493...
%e 3 11 1.{3}0529988...
%e 4 21 1.{4}0253353...
%e 5 39 1.{5}0239786...
%e 6 69 1.{6}0072440...
%e 7 119 1.{7}0065542...
%e 8 199 1.{8}0064508...
%e 9 323 1.{9}0020422...
%e 10 795 2.{10}021141...
%e 11 829 2.{11}000671...
%e 12 866 2.{12}026857...
%e ...
%e 99 19101 2.{99}001178...
%e 100 26440 3.{100}00492...
%e 101 26517 3.{101}00673... (End)
%Y Cf. A034064, A034084.
%K nonn,base
%O 0,1
%A _Patrick De Geest_, Sep 15 1998
%E Name edited by _Jon E. Schoenfield_, Dec 09 2017
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