|
|
A033589
|
|
a(n) = (2*n-1)*(3*n-1)*(4*n-1).
|
|
2
|
|
|
-1, 6, 105, 440, 1155, 2394, 4301, 7020, 10695, 15470, 21489, 28896, 37835, 48450, 60885, 75284, 91791, 110550, 131705, 155400, 181779, 210986, 243165, 278460, 317015, 358974, 404481, 453680, 506715
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,2
|
|
LINKS
|
|
|
FORMULA
|
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4). - Harvey P. Dale, Sep 22 2014
G.f.: (-1 +10*x +75*x^2 +60*x^3)/(1-x)^4. - R. J. Mathar, Feb 06 2017
a(n) = n^3 * Pochhammer(2 - 1/n, 3) = Product_{j=2..4} (j*n-1).
E.g.f.: (-1 + 7*x + 46*x^2 + 24*x^3)*exp(x). (End)
Sum_{n>=1} 1/a(n) = (sqrt(3)/2-1)*Pi + 8*log(2) - 9*log(3)/2. - Amiram Eldar, Feb 22 2022
|
|
MAPLE
|
|
|
MATHEMATICA
|
Table[Times@@(n*Range[2, 4]-1), {n, 0, 30}] (* or *) LinearRecurrence[{4, -6, 4, -1}, {-1, 6, 105, 440}, 30] (* Harvey P. Dale, Sep 22 2014 *)
|
|
PROG
|
(PARI) vector(31, n, my(m=n-1); prod(j=2, 4, j*m-1) ) \\ G. C. Greubel, Mar 05 2020
(Magma) [(2*n-1)*(3*n-1)*(4*n-1): n in [0..30]]; // G. C. Greubel, Mar 05 2020
(Sage) [product(j*n-1 for j in (2..4)) for n in (0..30)] # G. C. Greubel, Mar 05 2020
|
|
CROSSREFS
|
|
|
KEYWORD
|
sign,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|