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a(n) = floor(12/n).
0

%I #16 Apr 04 2023 22:57:51

%S 12,6,4,3,2,2,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%U 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0

%N a(n) = floor(12/n).

%t Floor[12/Range[100]] (* _Harvey P. Dale_, Jun 06 2022 *)

%o (Python)

%o def a(n): return 12//n

%o print([a(n) for n in range(1, 93)]) # _Michael S. Branicky_, Dec 06 2021

%o (Magma) [Floor(12/n): n in [1..100]]; // _Wesley Ivan Hurt_, Apr 04 2023

%Y Cf. A010766.

%K easy,nonn

%O 1,1

%A _Jeff Burch_