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a(n) = floor ( n(n+1)(n+2)(n+3) / (n+(n+1)+(n+2)+(n+3)) ).
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%I #15 Oct 18 2024 15:07:32

%S 0,2,8,20,38,64,100,148,208,282,373,480,606,753,921,1112,1328,1571,

%T 1841,2140,2471,2833,3229,3661,4129,4635,5182,5769,6399,7074,7794,

%U 8561,9377,10244,11162,12133,13160,14242,15382,16582,17842,19164

%N a(n) = floor ( n(n+1)(n+2)(n+3) / (n+(n+1)+(n+2)+(n+3)) ).

%H Harvey P. Dale, <a href="/A032767/b032767.txt">Table of n, a(n) for n = 0..1000</a>

%F The g.f. has denominator (1-x)^4(1-x^16). - _Ralf Stephan_, May 16 2005

%p A032767 := proc(n)

%p n*(n+1)*(n+2)*(n+3) /(4*n+6) ;

%p floor(%) ;

%p end proc: # _R. J. Mathar_, May 20 2013

%t Table[Floor[Times@@(n+Range[0,3])/Total[n+Range[0,3]]],{n,0,50}] (* _Harvey P. Dale_, Oct 18 2024 *)

%Y Cf. A032765-A032798.

%K nonn

%O 0,2

%A _Patrick De Geest_, May 15 1998