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%I #4 Mar 30 2012 18:56:21
%S 1,1,1,1,0,1,2,3,3,4,4,5,5,6,5,5,6,6,6,6,6,6,6,6,5,5,6,6,6,6,6,6,6,6,
%T 5,5,6,6,6,6,6,6,6,6,5,4,5,6,5,6,6,5,6,6,5,6,6,5,6,5,6,7,8,9,10,10,11,
%U 12,12,13,14,14,15,16,15,15,16,17,17,18,18,18
%N a(n)=(# 1's)-(# 0's) in first n terms of A031235.
%K nonn
%O 1,7
%A _Clark Kimberling_
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