%I #22 Sep 08 2022 08:44:50
%S 0,1,10,100,1000,10000,100000,107624,109573,132485,138624,159406,
%T 165640,192574,205738,215806,251894,281536,318725,419375,427863,
%U 568314,642510,713960,953867,954086,963218,965760,1000000,1008529,1023479
%N Numbers k such that k and k^3 have the same set of digits.
%C Conjecture: there exists some m and N for which a(n) = m + n for all n >= N. - _Charles R Greathouse IV_, Jun 28 2011
%H Nathaniel Johnston, <a href="/A029795/b029795.txt">Table of n, a(n) for n = 1..500</a>
%e 109573^3 = 1315559990715517. Since both numbers use the digits 0, 1, 3, 5, 7, 9, and no others, 109573 is in the sequence.
%p seq(`if`(convert(convert(n, base, 10), set) = convert(convert(n^3, base, 10), set), n, NULL), n=0..500000); # _Nathaniel Johnston_, Jun 28 2011
%t Select[Range[0, 199999], Union[IntegerDigits[#]] == Union[IntegerDigits[#^3]] &] (* _Alonso del Arte_, Jan 12 2020 *)
%o (Magma) [ n: n in [0..8*10^6] | Set(Intseq(n)) eq Set(Intseq(n^3)) ]; // _Bruno Berselli_, Jun 28 2011
%o (PARI) isA029795(n)=Set(Vec(Str(n)))==Set(Vec(Str(n^3))) \\ _Charles R Greathouse IV_, Jun 28 2011
%Y Cf. A029793, A029797, A232659-A232662.
%K nonn,base
%O 1,3
%A _Patrick De Geest_
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