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%I #11 Jan 25 2023 14:28:08
%S 1,32,655,10970,164281,2296172,30679075,397562990,5043607261,
%T 63029650112,779227037095,9558498208610,116583782365441,
%U 1416013883792852,17145682731588715,207132506435751830
%N Expansion of 1/((1-5x)(1-6x)(1-9x)(1-12x)).
%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (32,-369,1818,-3240).
%F G.f.: 1/((1-5*x)*(1-6*x)*(1-9*x)*(1-12*x)).
%F a(n) = (2*12^(n+3)-7*9^(n+3)+14*6^(n+3)-9*5^(n+3))/252. - _Yahia Kahloune_, Jun 03 2013
%F a(n) = 32*a(n-1) - 369*a(n-2) + 1818*a(n-3) - 3240*a(n-4). - _Wesley Ivan Hurt_, Jan 25 2023
%t CoefficientList[Series[1/((1-5x)(1-6x)(1-9x)(1-12x)),{x,0,20}],x] (* or *) LinearRecurrence[{32,-369,1818,-3240},{1,32,655,10970},20] (* _Harvey P. Dale_, Sep 26 2016 *)
%K nonn
%O 0,2
%A _N. J. A. Sloane_.