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Expansion of 1/((1-5x)(1-6x)(1-9x)(1-11x)).
1

%I #14 Jun 13 2015 00:49:08

%S 1,31,612,9842,140903,1874733,23747074,290631904,3469802325,

%T 40674188555,470287309856,5380934171886,61072079752867,

%U 688801372689097,7730331225654558,86417957138887388,963072515157938129

%N Expansion of 1/((1-5x)(1-6x)(1-9x)(1-11x)).

%H Harvey P. Dale, <a href="/A028175/b028175.txt">Table of n, a(n) for n = 0..958</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (31, -349, 1689, -2970).

%F a(n)=(2*11^(n+3)-5*9^(n+3)+8*6^(n+3)-5^(n+4))/120. [_Yahia Kahloune_, Jun 03 2013]

%t CoefficientList[Series[1/((1-5x)(1-6x)(1-9x)(1-11x)),{x,0,30}],x] (* or *) LinearRecurrence[{31,-349,1689,-2970},{1,31,612,9842},30] (* _Harvey P. Dale_, Nov 18 2014 *)

%o (PARI) x='x+O('x^66); Vec(1/((1-5*x)*(1-6*x)*(1-9*x)*(1-11*x))) \\ _Joerg Arndt_, Jun 03 2013

%K nonn

%O 0,2

%A _N. J. A. Sloane_.