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A025832 Expansion of 1/((1-x^3)(1-x^4)(1-x^10)). 0

%I #22 May 23 2021 02:56:11

%S 1,0,0,1,1,0,1,1,1,1,2,1,2,2,2,2,3,2,3,3,4,3,4,4,5,4,5,5,6,5,7,6,7,7,

%T 8,7,9,8,9,9,11,9,11,11,12,11,13,12,14,13,15,14,16,15,17,16,18,17,19,

%U 18,21,19,21,21,23,21,24,23

%N Expansion of 1/((1-x^3)(1-x^4)(1-x^10)).

%C Number of partitions of n into parts 3, 4, and 10. - _Joerg Arndt_, Aug 28 2013

%H <a href="/index/Rec#order_17">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,1,1,0,0,-1,0,0,1,0,0,-1,-1,0,0,1).

%F a(n) = a(n-3) + a(n-4) - a(n-7) + a(n-10) - a(n-13) - a(n-14) + a(n-17). - _R. J. Mathar_, Jun 04 2013

%t CoefficientList[Series[1/((1-x^3)(1-x^4)(1-x^10)),{x,0,70}],x] (* _Harvey P. Dale_, May 03 2021 *)

%o (PARI) a(n)=floor((n%3<2)/3+(-1)^(n\5)/10+(2*n^2+34*n+221)/480+(2*n+17)*(-1)^n/160); \\ _Tani Akinari_, Aug 28 2013

%K nonn,easy

%O 0,11

%A _N. J. A. Sloane_

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