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a(n) = Sum_{i=1..floor((n+2)/4)} a(2i-1)*a(n-2i+1), with a(1)=a(2)=1 and a(3)=2.
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%I #7 Jul 30 2019 06:38:57

%S 1,1,2,2,2,6,10,14,26,50,90,162,290,622,1186,2206,4274,8802,17378,

%T 33538,65986,136790,274282,540686,1082698,2238978,4537082,9091330,

%U 18322466,38230558,78041890,157766622,321334306,670282690,1377130434,2806589186

%N a(n) = Sum_{i=1..floor((n+2)/4)} a(2i-1)*a(n-2i+1), with a(1)=a(2)=1 and a(3)=2.

%K nonn

%O 1,3

%A _Clark Kimberling_

%E Offset corrected and title improved by _Sean A. Irvine_, Jul 30 2019