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a(n) = Sum_{i=1..floor((n+1)/4)} a(2*i-1) * a(n-2*i+1), with a(1)=a(2)=1 and a(3)=2.
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%I #7 Jul 21 2019 13:27:09

%S 1,1,2,2,2,2,6,10,14,26,50,90,162,290,582,1090,2006,3794,7458,14306,

%T 27074,51762,103062,200410,385070,747274,1492050,2929754,5702258,

%U 11151778,22397270,44268562,86834790,171256770,344480610,684714338,1352345666

%N a(n) = Sum_{i=1..floor((n+1)/4)} a(2*i-1) * a(n-2*i+1), with a(1)=a(2)=1 and a(3)=2.

%K nonn

%O 1,3

%A _Clark Kimberling_