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a(n) = [ 1/{n*sqrt(6)} ], where {x} := x - [ x ].
3

%I #8 Aug 03 2014 14:27:15

%S 2,1,2,1,4,1,6,1,22,2,1,2,1,3,1,5,1,11,1,1,2,1,2,1,4,1,7,1,28,2,1,2,1,

%T 3,1,5,1,12,1,1,2,1,3,1,4,1,7,1,40,2,1,2,1,3,1,5,1,14,1,1,2,1,3,1,4,1,

%U 8,1,67,2,1,2,1,3,1,6,1,16,1,1,2,1,3,1,4,1,9,1,218,2,1,2,1,3

%N a(n) = [ 1/{n*sqrt(6)} ], where {x} := x - [ x ].

%H Clark Kimberling, <a href="/A024559/b024559.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[Floor[1/FractionalPart[n*Sqrt[6]]], {n, 1, 100}]

%t (* _Clark Kimberling_, Aug 16 2012 *)

%Y Cf. A024558.

%K nonn

%O 1,1

%A _Clark Kimberling_

%E Corrected by _Clark Kimberling_, Aug 16 2012