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If any power of 2 ends with k 7's and 8's, they must be the first k terms of this sequence in reverse order.
4

%I #13 Jan 27 2022 22:48:08

%S 8,8,8,7,7,8,7,8,7,8,8,8,8,8,7,8,8,8,7,8,8,8,8,8,7,7,8,8,7,8,8,7,8,7,

%T 8,8,8,7,8,7,8,7,7,8,8,7,8,7,7,7,8,8,8,8,7,7,8,7,8,8,8,7,7,7,8,7,8,8,

%U 7,7,7,8,7,7,8,8,7,8,8,8,7,8,8,7,8,7,8,8,7,7,8,8,7,8,8,7,8,8,7,8,7,8,7,8,7,8,8,8

%N If any power of 2 ends with k 7's and 8's, they must be the first k terms of this sequence in reverse order.

%H Ray Chandler, <a href="/A023414/b023414.txt">Table of n, a(n) for n = 1..10000</a>

%K nonn,base

%O 1,1

%A _David W. Wilson_