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If any power of 2 ends with k 5's and 8's, they must be the first k terms of this sequence in reverse order.
3

%I #13 Jan 27 2022 22:47:57

%S 8,8,8,5,8,8,8,5,5,8,5,8,5,8,5,5,5,8,8,8,8,5,5,5,8,5,8,5,5,5,8,8,5,8,

%T 8,5,5,8,5,8,5,8,8,8,5,5,5,8,8,8,5,8,8,8,8,8,5,8,5,5,8,5,5,8,5,8,8,5,

%U 8,8,5,8,5,8,5,8,8,5,8,8,5,8,5,8,5,5,8,5,5,8,8,5,8,5,5,8,8,5,5,5,5,8,8,8,8,8,5,5

%N If any power of 2 ends with k 5's and 8's, they must be the first k terms of this sequence in reverse order.

%H Ray Chandler, <a href="/A023413/b023413.txt">Table of n, a(n) for n = 1..10000</a>

%K nonn,base

%O 1,1

%A _David W. Wilson_