%I #13 Jan 27 2022 22:45:26
%S 4,4,5,4,4,4,4,5,4,5,4,5,5,5,5,4,4,5,4,5,4,5,5,4,5,5,4,5,4,5,5,4,4,4,
%T 4,5,4,5,4,5,4,4,4,5,5,5,5,4,4,5,5,5,4,5,4,4,5,5,5,5,4,5,5,4,5,5,4,5,
%U 5,5,5,5,4,4,5,4,5,5,5,5,5,4,4,5,5,4,4,5,5,4,5,4,5,4,5,4,5,4,5,4,5,4,4,5,4,5,5,4
%N If any power of 2 ends with k 4's and 5's, they must be the first k terms of this sequence in reverse order.
%H Ray Chandler, <a href="/A023403/b023403.txt">Table of n, a(n) for n = 1..10000</a>
%K nonn,base
%O 1,1
%A _David W. Wilson_